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满二叉树知前序求后序
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发布时间:2019-03-01

本文共 214 字,大约阅读时间需要 1 分钟。

/*** 满二叉树的根结点把二叉树划分为两个结点数量相同的子树,以此类推*/Elem stack[MAX];int top = -1;void preToPost(Elem e[], int s, int t) {   	if(s > t) return;	stack[++top] = e[s];	preToPost(e, (s + t)/2 + 1, t);	preToPost(e, s + 1, (s + t)/2);}

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